题目内容
(1)化简
;
(2)若cosθ=
,求
的值.
| ||
sin170°-
|
(2)若cosθ=
| ||
| 4 |
sin(θ-5π)cos(-
| ||
sin(θ-
|
(1)
=
=
=-1.
(2)
=
=-sinθ=±
=±
,
若θ为一象限角,则原式=-
;若θ为四象限角,则原式=
.
| ||
sin170°-
|
| |sin10°-cos10°| |
| sin10°-cos10° |
| cos10°-sin10° |
| sin10°-cos10° |
(2)
sin(θ-5π)cos(-
| ||
sin(θ-
|
| -sinθ•(-sinθ)cosθ |
| cosθ(-sinθ) |
| 1-cos2θ |
| 3 |
| 4 |
若θ为一象限角,则原式=-
| 3 |
| 4 |
| 3 |
| 4 |
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