题目内容
如图,已知AA1与BB1是异面直线,且AA1=2,BB1=1,AB⊥BB1,A1B1⊥BB1,则AA1与BB1所成的角为( )

| A.30° | B.45° | C.60° | D.90° |
设AA1与BB1所成的角为θ,由两个向量的数量积的定义可得
•
=1×2 cosθ.
又
•
=(
+
+
)•(BB1)=0+
2+0=1,
故1×2 cosθ=1,∴cosθ=
,故θ=60°,
故选C.
| AA1 |
| BB1 |
又
| AA1 |
| BB1 |
| AB |
| BB1 |
| B1A1 |
| BB1 |
故1×2 cosθ=1,∴cosθ=
| 1 |
| 2 |
故选C.
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