题目内容
在△AOB中,OA=5,OB=3,AB的垂直平分线l交AB于点C,P是l上的任意一点,则
•(
-
)的值为 .
| OP |
| OB |
| OA |
考点:平面向量数量积的运算
专题:平面向量及应用
分析:由AB的垂直平分线l交AB于点C,可得
=
(
+
),于是
=
+
=
(
+
)+
,代入可得
•(
-
)=[
(
+
)+
]•
.
| OC |
| 1 |
| 2 |
| OA |
| OB |
| OP |
| OC |
| CP |
| 1 |
| 2 |
| OA |
| OB |
| CP |
| OP |
| OB |
| OA |
| 1 |
| 2 |
| OA |
| OB |
| CP |
| AB |
解答:
解:如图所示,
∵AB的垂直平分线l交AB于点C,
∴
=
(
+
),
∴
=
+
=
(
+
)+
,
∴
•(
-
)=[
(
+
)+
]•
=
(
+
)•(
-
)
=
(
2-
2)
=
(32-52)
=-8.
故答案为:-8.
∵AB的垂直平分线l交AB于点C,
∴
| OC |
| 1 |
| 2 |
| OA |
| OB |
∴
| OP |
| OC |
| CP |
| 1 |
| 2 |
| OA |
| OB |
| CP |
∴
| OP |
| OB |
| OA |
| 1 |
| 2 |
| OA |
| OB |
| CP |
| AB |
=
| 1 |
| 2 |
| OA |
| OB |
| OB |
| OA |
=
| 1 |
| 2 |
| OB |
| OA |
=
| 1 |
| 2 |
=-8.
故答案为:-8.
点评:本题考查了向量的平行四边形法则、数量积运算及其性质、向量垂直与数量积的关系,考查了推理能力和计算能力,属于中档题.
练习册系列答案
相关题目