题目内容
已知△ABC中,
=
,
=
,
•
<0,S△ABC=
,|
|=3,|
|=5,则
与
的夹角为( )
| CB |
| a |
| CA |
| b |
| a |
| b |
| 15 |
| 4 |
| a |
| b |
| a |
| b |
| A.30° | B.60° | C.120° | D.150° |
因为S△ABC=
|
•
|=
|
||
|sin(
,
)=
sin(
,
)=
,
所以sin(
,
)=
,
则(
,
)=30°或150°
又
•
<0,所以(
,
)=150°,
即
与
的夹角为150°.
故选D
| 1 |
| 2 |
| a |
| b |
| 1 |
| 2 |
| a |
| b |
| a |
| b |
| 15 |
| 2 |
| a |
| b |
| 15 |
| 4 |
所以sin(
| a |
| b |
| 1 |
| 2 |
则(
| a |
| b |
又
| a |
| b |
| a |
| b |
即
| a |
| b |
故选D
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,S△ABC=
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与
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| CB |
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| a |
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| 4 |
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| 4 |
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已知△ABC中,
=
,
=
,
•
<0,S△ABC=
,|
|=3,|
|=5,则
与
的夹角为( )
| CB |
| a |
| CA |
| b |
| a |
| b |
| 15 |
| 4 |
| a |
| b |
| a |
| b |
| A、30° | B、60° |
| C、120° | D、150° |