题目内容
已知sin(
-α)+sinα=
,则sin(α+
)=______.
| 2π |
| 3 |
4
| ||
| 5 |
| 7π |
| 6 |
∵sin(
-α)+sinα=
,
展开可得,
cosα+
sinα=
∴
cosα+
sinα=
由辅助角公式可得sin(α+
)=
则sin(α+
)=-sin(α+
)=-
故答案为:-
| 2π |
| 3 |
4
| ||
| 5 |
展开可得,
| ||
| 2 |
| 3 |
| 2 |
4
| ||
| 5 |
∴
| 1 |
| 2 |
| ||
| 2 |
| 4 |
| 5 |
由辅助角公式可得sin(α+
| π |
| 6 |
| 4 |
| 5 |
则sin(α+
| 7π |
| 6 |
| π |
| 6 |
| 4 |
| 5 |
故答案为:-
| 4 |
| 5 |
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相关题目
已知sin(
-α)+sinα=
,则sin(α+
)的值是( )
| 2π |
| 3 |
4
| ||
| 5 |
| 7π |
| 6 |
A、-
| ||||
B、
| ||||
C、-
| ||||
D、
|