题目内容
| lim |
| x→1 |
| x2-1 |
| 2x2-x-1 |
| A．0 | B．1 | C．
| D．
|
原式=
=
=
，
故选D．
| lim |
| x→1 |
| (x+1)(x-1) |
| (x-1)(2x+1) |
| lim |
| x→1 |
| x+1 |
| 2x+1 |
| 2 |
| 3 |
故选D．
练习册系列答案
相关题目
题目内容
| lim |
| x→1 |
| x2-1 |
| 2x2-x-1 |
| A．0 | B．1 | C．
| D．
|
| lim |
| x→1 |
| (x+1)(x-1) |
| (x-1)(2x+1) |
| lim |
| x→1 |
| x+1 |
| 2x+1 |
| 2 |
| 3 |