题目内容
16.点集$M=\left\{{({x,y})\left|{\left\{\begin{array}{l}x=3cosθ\\ y=3sinθ\end{array}\right.θ是参数,0<θ<π}\right.}\right\}$,N={(x,y)|y=x+b},若M∩N≠∅,则b应满足( )| A. | $-3\sqrt{2}≤b≤3\sqrt{2}$ | B. | $-3\sqrt{2}<b<-3$ | C. | $0≤b≤3\sqrt{2}$ | D. | $-3<b≤3\sqrt{2}$ |
分析 将M中参数方程化为普通方程,根据M与N的交集不为空集求出出b的范围.
解答
解:由M中参数方程变形得:x2+y2=9(-3<x<3,0<y<3),
与N中方程联立得:$\left\{\begin{array}{l}{{x}^{2}+{y}^{2}=9}\\{y=x+b}\end{array}\right.$,
消去y得:2x2+2bx+b2-9=0,
令△=4b2-8(b2-9)=-4b2+72=0,即b=3$\sqrt{2}$(负值舍去),
∵M∩N≠∅,
∴由图象得:两函数有交点,
则b满足-3<b≤3$\sqrt{2}$,
故选:D.
点评 此题考查了交集及其运算,熟练掌握交集的定义是解本题的关键.
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