题目内容


A(x1y1),B(x2y2)是抛物线y2=2px(p>0)上的两点,并且满足OAOB,则y1y2等于(  )

A.-4p2                                                       B.-3p2

C.-2p2                                                       D.-p2


A

[解析] ∵OAOB,∴=0.①

x1x2y1y2=0.

AB都在抛物线上,

代入①得·y1y2=0,解得y1y2=-4p2.


练习册系列答案
相关题目

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网