Question

ÏÂÁÐÈÜÒºÖи÷΢Á£µÄŨ¶È¹ØϵÕýÈ·µÄÊÇ£¨¡¡¡¡£©

• A¡¢0.1mol?L^-1HCOOHÈÜÒºÖУºc£¨HCOO^-£©+c£¨OH^-£©=c£¨H⁺£©
• B¡¢0.1mol?L^-1NaHCO₃ÈÜÒºÖУºc£¨Na⁺£©+c£¨H⁺£©Ê®c£¨H₂CO₃£©=c£¨HCO₃^-£©+2c£¨CO₃^2-£©
• C¡¢µÈÌå»ý¡¢µÈÎïÖʵÄÁ¿Å¨¶ÈµÄNaXºÍÈõËáHX»ìºÏºóµÄÈÜÒºÖУºc£¨Na⁺£©£¾c£¨HX£©£¾c£¨X^-£©£¾c£¨H⁺£©£¾c£¨OH^-£©
• D¡¢µÈÎïÖʵÄÁ¿Å¨¶ÈµÄÁòËáÓë´×ËáÄÆÈÜÒºµÈÌå»ý»ìºÏ£º2c£¨SO₄^2-£©+c£¨OH^-£©=c£¨H⁺£©+c£¨CH₃COOH£©

Answer 1

¿¼µã£ºÀë×ÓŨ¶È´óСµÄ±È½Ï

רÌ⣺

·ÖÎö£ºA¡¢ÒÀ¾ÝÈÜÒºÖеçºÉÊغã·ÖÎö£»
B¡¢ÒÀ¾ÝÈÜÒºÖеçºÉÊغã·ÖÎöÅжϣ»
C¡¢µÈÌå»ý¡¢µÈÎïÖʵÄÁ¿Å¨¶ÈµÄNaXºÍÈõËáHX»ìºÏÈÜÒº¿ÉÄÜÏÔËáÐÔ»ò¼îÐÔ£»
D¡¢ÁòËáÓë´×ËáÄÆÈÜÒºµÈÌå»ý»ìºÏºó·¢Éú·´Ó¦£¬¸ù¾ÝÈÜÒºµÄ×é³ÉÇé¿öÀ´È·¶¨Àë×ÓŨ¶ÈÖ®¼äµÄ¹Øϵ£»

½â´ð£º ½â£ºA¡¢0.1mol?L^-1HCOOHÈÜÒºÖдæÔÚµçºÉÊغ㣺c£¨HCOO^-£©+c£¨OH^-£©=c£¨H⁺£©£¬¹ÊAÕýÈ·£»
B¡¢0.1mol?L^-1NaHCO₃ÈÜÒºÖдæÔÚµçºÉÊغ㣺c£¨Na⁺£©+c£¨H⁺£©=c£¨HCO₃^-£©+2c£¨CO₃^2-£©+c£¨OH^-£©£¬¹ÊB´íÎó£»
C¡¢µÈÌå»ý¡¢µÈÎïÖʵÄÁ¿Å¨¶ÈµÄNaXºÍÈõËáHX»ìºÏºóµÄÈÜÒºÖУ¬µçÀëºÍË®½â³Áµí²»Öª²»ÄÜÅжÏÈÜÒºËá¼îÐÔ£¬¹ÊC´íÎó£º
D¡¢µÈÎïÖʵÄÁ¿Å¨¶ÈµÄÁòËáÓë´×ËáÄÆÈÜÒºµÈÌå»ý»ìºÏ£¬ËùµÃÈÜÒºÖк¬ÓÐÊ£ÓàµÄÁòËá¡¢Éú³ÉµÄÁòËáÄÆÒÔ¼°´×Ëᣬ¸ù¾ÝµçºÉÊغ㣺c£¨Na⁺£©+c£¨H⁺£©=2c£¨SO₄^2-£©+c£¨OH^-£©+c£¨CH₃COO^-£©£¬ÁòËá¸ùŨ¶ÈºÍÄÆÀë×ÓŨ¶ÈÏàµÈ£¬ËùÒÔc£¨H⁺£©=c£¨SO₄^2-£©+c£¨OH^-£©+c£¨CH₃COO^-£©£¬¼´c£¨SO₄^2-£©+c£¨OH^-£©=c£¨H⁺£©-c£¨CH₃COO^-£©£¬¹ÊD´íÎó£»
¹ÊÑ¡A£®

µãÆÀ£º±¾Ì⿼²éÁ˵ç½âÖÊÈÜÒºÖÐÀë×ÓŨ¶È´óС£¬µçºÉÊغ㣬ÎïÁÏÊغãµÄ·ÖÎöÅжϣ¬ÕÆÎÕ»ù´¡Êǹؼü£¬ÌâÄ¿ÄѶÈÖеȣ®