ÌâÄ¿ÄÚÈÝ

2£®Ê¹Ò»¶¨Á¿µÄпÓë100mL 18.5mol/LµÄŨÁòËá³ä·Ö·´Ó¦ºó£¬Ð¿ÍêÈ«Èܽ⣬ͬʱÉú³É±ê×¼×´¿öÏÂµÄÆøÌåA¹²33.6L£¬½«·´Ó¦ºóµÄÈÜҺϡÊ͵½1.00L£¬²âµÃ¸ÃÈÜÒºÖÐc£¨H+£©=0.100mol/L£®
£¨1£©·ÖÎö·´Ó¦¹ý³ÌÖÐÆøÌå²úÎïµÄ±ä»¯Çé¿ö£¬²¢Óû¯Ñ§·½³Ìʽ
£¨2£©ÇóÆøÌåAÖи÷³É·ÖµÄÌå»ý±È£®
£¨3£©Ïò·´Ó¦ºóµÄÈÜÒºÖмÓÈë×ãÁ¿µÄBaCl2ÈÜÒº£¬Çó¿ÉÉú³É³ÁµíµÄÖÊÁ¿£®

·ÖÎö £¨1£©Ð¿ÓëŨÁòËá·¢Éú£ºZn+2H2SO4=ZnSO4+SO2¡ü+H2O£¬Ëæ×Å·´Ó¦µÄ½øÐУ¬ÁòËáŨ¶È½µµÍ£¬·¢Éú£ºZn+H2SO4=ZnSO4+H2¡ü£»
£¨2£©Éú³ÉÆøÌåΪSO2ºÍH2µÄ»ìºÏÎÓÉ·½³Ìʽ¿ÉÖª£ºn£¨Zn£©=n£¨SO2+H2£©£¬¸ù¾Ým=nM¼ÆËãZnµÄÖÊÁ¿£»¼ÆËãÊ£ÓàÁòËáÎïÖʵÄÁ¿£¬½ø¶ø¼ÆËã²Î¼Ó·´Ó¦ÁòËáÎïÖʵÄÁ¿£¬ÉèÉè·´Ó¦Éú³ÉxmolSO2£¬ymolH2£¬±íʾ³ö¸÷·´Ó¦ÏûºÄÁòËáÎïÖʵÄÁ¿£¬ÔÙ½áºÏ¶þÕßÎïÖʵÄÁ¿Áз½³Ì¼ÆËã½â´ð£»
£¨3£©¸ù¾ÝÁòÊØºã·ÖÎö£¬½áºÏm=nM¼ÆË㣮

½â´ð ½â£º£¨1£©Ð¿ÓëŨÁòËá·¢Éú£ºZn+2H2SO4=ZnSO4+SO2¡ü+H2O£¬Ëæ×Å·´Ó¦µÄ½øÐУ¬ÁòËáŨ¶È½µµÍ£¬·¢Éú£ºZn+H2SO4=ZnSO4+H2¡ü£¬¹Ê´ð°¸Îª£ºZn+2H2SO4=ZnSO4+SO2¡ü+H2O£»Zn+H2SO4=ZnSO4+H2¡ü£»
£¨2£©Éú³ÉÆøÌåΪSO2ºÍH2µÄ»ìºÏÎÓÉ·½³Ìʽ¿ÉÖª£ºn£¨Zn£©=n£¨SO2+H2£©=$\frac{33.6L}{22.4L/mol}$=1.5mol£¬¹ÊZnµÄÖÊÁ¿=1.5mol¡Á65g/mol=97.5g£¬ÈÜҺʣÓàÁòËáµÄÎïÖʵÄÁ¿Îª $\frac{1}{2}$¡Á1L¡Á0.1mol/L=0.05mol£¬
²Î¼Ó·´Ó¦µÄn£¨H2SO4£©=0.1L¡Á18.5mol/L-0.05mol=1.8mol£¬
Éè·´Ó¦Éú³ÉxmolSO2£¬ymolH2£¬Ôò£º
Zn+2H2SO4£¨Å¨£©=ZnSO4+SO2¡ü+H2O
x        2x                             x
Zn+H2SO4£¨Ï¡£©=ZnSO4+H2¡ü
y        y                           y
ÓÉÌâÒâ¿ÉµÃ $\left\{\begin{array}{l}{x+y=1.5}\\{2x+y=1.8}\end{array}\right.$£¬
½âµÃ£ºx=0.3mol   y=1.2mol
V£¨SO2£©£ºV£¨H2£©=0.3mol£º1.2mol=1£º4
´ð£ºÆøÌåAÖÐV£¨SO2£©£ºV£¨H2£©=1£º4£»
£¨3£©¸ù¾ÝÁòÊØºã£¬ËùÒÔn£¨BaSO4£©=£¨1.85-0.3£©mol¡Á233g/mol=361.15g£¬´ð£ºÉú³É³ÁµíµÄÖÊÁ¿361.15g£®

µãÆÀ ±¾Ì⿼²é·½³ÌʽµÄÏà¹Ø¼ÆË㣬עÒâ¸ù¾Ý·½³Ìʽ¼ÆËãÈ·¶¨ZnÓëÆøÌåµÄÎïÖʵÄÁ¿¹ØÏµ£¬ÄѶȲ»´ó£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
13£®ÔªËØA¡¢B¡¢C¡¢D¡¢E¡¢F¡¢GÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃÈçͼ1Ëùʾ£¬»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©GµÄ»ù̬ԭ×ÓºËÍâµç×ÓÅŲ¼Ê½Îª1s22s22p63s23p63d64s2£®Ô­×ӵĵÚÒ»µçÀëÄÜ£ºD£¼E£¨Ìî¡°£¾¡±»ò¡°£¼¡±£©£®
£¨2£©¸ù¾Ý¼Û²ãµç×Ó»¥³âÀíÂÛ£¬¼Û²ãµç×Ó¶ÔÖ®¼äµÄ³âÁ¦´óСÓÐÈçÏÂ˳Ðò£ºl-l£¾l-b£¾b-b£¨lΪ¹Â¶Ôµç×Ó¶Ô£¬bΪ¼üºÏµç×Ó¶Ô£©£¬Ôò¹ØÓÚA2CÖеÄA-C-A¼ü½Ç¿ÉµÃ³öµÄ½áÂÛÊÇD£®
A£®180¡ã                       B£®½Ó½ü120¡ã£¬µ«Ð¡ÓÚ120¡ã
C£®½Ó½ü120¡ã£¬µ«´óÓÚ120¡ã     D£®½Ó½ü109¡ã28¡ä£¬µ«Ð¡ÓÚ109¡ã28¡ä
£¨3£©»¯ºÏÎïG£¨BC£©5µÄÈÛµãΪ-20¡æ£¬·ÐµãΪ103¡æ£¬Æä¹ÌÌåÊôÓÚ·Ö×Ó¾§Ì壬¸ÃÎïÖÊÖдæÔڵĻ¯Ñ§¼üÀàÐÍÓÐÅäλ¼ü¡¢¹²¼Û¼ü£¬ËüÔÚ¿ÕÆøÖÐȼÉÕÉú³ÉºìרɫÑõ»¯Î·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ4Fe£¨CO£©3+9O2$\frac{\underline{\;\;¡÷\;\;}}{\;}$2Fe2O3+12CO2£®
£¨4£©»¯ºÏÎïBCF2µÄÁ¢Ìå¹¹ÐÍÎªÆ½ÃæÈý½ÇÐΣ¬ÆäÖÐBÔ­×ÓµÄÔÓ»¯¹ìµÀÀàÐÍÊÇsp2£¬Ð´³öÁ½¸öÓëBCF2¾ßÓÐÏàͬ¿Õ¼ä¹¹Ð͵ĺ¬ÑõËá¸ùÀë×ÓNO3-¡¢CO32-µÈ£®
£¨5£©»¯ºÏÎïECµÄ¾§°û½á¹¹Èçͼ2Ëùʾ£¬¾§°û²ÎÊýa=0.424nm£®Ã¿¸ö¾§°ûÖк¬ÓÐ4¸öE2+£¬ÁÐʽ¼ÆËãEC¾§ÌåµÄÃܶÈ3.49g•cm-3£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø