ÌâÄ¿ÄÚÈÝ

18£®°´ÒªÇóÊéд·½³Ìʽ£º
£¨1£©¹ýÑõ»¯ÄÆÓëCO2·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º2Na2O2+2CO2=2Na2CO3+O2
£¨2£©½«ÉÙÁ¿Æ«ÂÁËáÄÆÈÜÒºµÎÈë×ãÁ¿ÑÎËáµÄÀë×Ó·½³Ìʽ£ºAlO2-+4H+=Al3++2H2O
£¨3£©ÌúÓë¸ßÎÂË®ÕôÆø·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º3Fe+4H2O£¨g£©$\frac{\underline{\;¼ÓÈÈ\;}}{\;}$Fe3O4+4H2
£¨4£©Ã¾ÌõÔÚ¶þÑõ»¯Ì¼ÖÐȼÉյĻ¯Ñ§·½³Ìʽ£º2Mg+CO2$\frac{\underline{\;µãȼ\;}}{\;}$2MgO+C£®

·ÖÎö £¨1£©¹ýÑõ»¯ÄÆÓëCO2·´Ó¦Éú³É̼ËáÄÆºÍÑõÆø£»
£¨2£©½«ÉÙÁ¿Æ«ÂÁËáÄÆÈÜÒºµÎÈë×ãÁ¿ÑÎËᣬ»á²úÉúÂÈ»¯ÂÁÈÜÒº£»
£¨3£©ÌúÓë¸ßÎÂË®ÕôÆø·´Ó¦Éú³ÉËÄÑõ»¯ÈýÌúºÍÇâÆø£»
£¨4£©Ã¾ÌõÔÚ¶þÑõ»¯Ì¼ÖÐȼÉÕÉú³ÉÑõ»¯Ã¾ºÍ̼£®

½â´ð ½â£º£¨1£©¹ýÑõ»¯ÄÆÓëCO2·´Ó¦Éú³É̼ËáÄÆºÍÑõÆø£¬¼´£º2Na2O2+2CO2=2Na2CO3+O2£¬¹Ê´ð°¸Îª£º2Na2O2+2CO2=2Na2CO3+O2£»
£¨2£©½«ÉÙÁ¿Æ«ÂÁËáÄÆÈÜÒºµÎÈë×ãÁ¿ÑÎËᣬ»á²úÉúÂÈ»¯ÂÁÈÜÒº£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪ£ºAlO2-+4H+=Al3++2H2O£¬¹Ê´ð°¸Îª£ºAlO2-+4H+=Al3++2H2O£»
£¨3£©ÌúÓë¸ßÎÂË®ÕôÆø·´Ó¦Éú³ÉËÄÑõ»¯ÈýÌúºÍÇâÆø£¬¼´3Fe+4H2O£¨g£©$\frac{\underline{\;\;¡÷\;\;}}{\;}$Fe3O4+4H2£¬¹Ê´ð°¸Îª£º3Fe+4H2O£¨g£©$\frac{\underline{\;\;¡÷\;\;}}{\;}$Fe3O4+4H2£»
£¨4£©Ã¾ÌõÔÚ¶þÑõ»¯Ì¼ÖÐȼÉÕÉú³ÉÑõ»¯Ã¾ºÍ̼£¬¼´2Mg+CO2$\frac{\underline{\;µãȼ\;}}{\;}$2MgO+C£¬¹Ê´ð°¸Îª£º2Mg+CO2$\frac{\underline{\;µãȼ\;}}{\;}$2MgO+C£®

µãÆÀ ±¾Ì⿼²éÁËÀë×Ó·½³Ìʽ¡¢»¯Ñ§·½³ÌʽµÄÊéд£¬ÌâÄ¿ÄѶÈÖеȣ¬Ã÷È·Àë×Ó·½³Ìʽ¡¢»¯Ñ§·½³ÌʽÊÇÊéдԭÔòΪ½â´ð¹Ø¼ü£¬ÊÔÌâ²àÖØ¿¼²éѧÉúµÄ·ÖÎö¡¢Àí½âÄÜÁ¦¼°Áé»îÓ¦Óûù´¡ÖªÊ¶µÄÄÜÁ¦£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
6£®ÒÑÖªA¡¢B¡¢C¡¢D¡¢E¡¢FΪǰËÄÖÜÆÚµÄÁùÖÖÔªËØ£¬Ô­×ÓÐòÊýÒÀ´ÎÔö´ó£¬ÆäÖÐAλÓÚÖÜÆÚ±íµÄsÇø£¬ÆäÔ­×ÓÖеç×Ó²ãÊýºÍδ³É¶Ôµç×ÓÊýÏàͬ£»BÔ­×Ó¼Ûµç×ÓÅŲ¼Ê½Îªnsnnpn£¬BºÍEͬÖ÷×壬DÔ­×ÓµÄ×îÍâ²ãµç×ÓÊýÊÇÆäÄÚ²ãµÄ3±¶£»FÔªËØÎ»ÓÚÔªËØÖÜÆÚ±íµÄµÚËÄÐС¢µÚʮһÁУ®ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©»ù̬FÔ­×ӵĺËÍâµç×ÓÅŲ¼Ê½Îª1s22s22p63s23p63d104s1£®
£¨2£©¹ØÓÚB2A2µÄÏÂÁÐ˵·¨ÖÐÕýÈ·µÄÊÇ£¨ÌîÑ¡ÏîÐòºÅ£©¢Û¢Ü£®
¢ÙB2A2ÖеÄËùÓÐÔ­×Ó¶¼Âú×ã8µç×ÓÎȶ¨½á¹¹
¢Úÿ¸öB2A2·Ö×ÓÖЦҼüºÍ¦Ð¼üÊýÄ¿±ÈΪ1£º1
¢ÛB2A2ÊÇÓɼ«ÐÔ¼üºÍ·Ç¼«ÐÔ¼ü¹¹ÐγɵķǼ«ÐÔ·Ö×Ó
¢ÜB2A2ÖÐÐÄÔ­×ÓµÄÔÓ»¯ÀàÐÍΪspÔÓ»¯
£¨3£©B¡¢C¡¢DÈýÖÖÔªËØµÚÒ»µçÀëÄܰ´ÓÉ´óµ½Ð¡µÄ˳ÐòÅÅÁÐΪN£¾O£¾C £¨ÓÃÔªËØ·ûºÅ±íʾ£©£®
£¨4£©CµÄÆøÌ¬Ç⻯ÎïÓëCµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯Îï·´Ó¦Éú³ÉÒ»ÖÖÑÎH£¬H¾§ÌåÖдæÔڵĻ¯Ñ§¼üÀàÐÍÓТ٢ڢܣ¨ÌîÑ¡ÏîÐòºÅ£©£®
¢ÙÀë×Ó¼ü¢Ú¹²¼Û¼ü¢ÛÇâ¼ü¢ÜÅäλ¼ü¢Ý½ðÊô¼ü
£¨5£©»ù̬EÔ­×ÓµÄ×î¸ßÄܲã¾ßÓеÄÔ­×Ó¹ìµÀÊýΪ4£»BºÍE·Ö±ðÓëÑõÔªËØÐγɵÄ×î¸ß¼ÛÑõ»¯ÎïÖУ¬È۷еã½Ï¸ßµÄÊÇSiO2£¨Ð´»¯Ñ§Ê½£©£®
£¨6£©Fµ¥Öʵľ§Ìå¶Ñ»ý·½Ê½ÎªÃæÐÄÁ¢·½£¬ÆäÅäλÊýΪ12£»ÈôFµÄÏà¶Ô·Ö×ÓÖÊÁ¿ÎªM£¬ËüµÄ¾§°ûÀⳤΪa£¨cm£©£¬ÔòF¾§ÌåµÄÃܶÈΪ$\frac{4M}{{N}_{A¡Á{a}^{3}}}$g•cm-3£®£¨°¢·üÙ¤µÂÂÞ³£ÊýΪNA£©

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø