ÌâÄ¿ÄÚÈÝ

5£®ºÏ³É°±¹¤Òµ¶Ô¹úÃñ¾­¼ÃºÍÉç»á·¢Õ¹¾ßÓÐÖØÒªµÄÒâÒ壮ÆäÔ­ÀíΪ£º
N2£¨g£©+3H2£¨g£©?2NH3£¨g£©¡÷H=-92.4kJ/mol    ¾Ý´Ë»Ø´ðÒÔÏÂÎÊÌ⣺
£¨1£©ºÏ³É°±¹¤Òµ²ÉÈ¡µÄÏÂÁдëÊ©ÖУ¬²»ÄÜÓÃÀÕÉ³ÌØÁÐÔ­Àí½âÊ͵ÄÊÇ¢Ú¢Û£¨ÌîÐòºÅ£©£®
¢Ù20Mpa¡«50Mpa   ¢Ú500¡æµÄ¸ßΠ   ¢ÛÌú´¥Ã½×÷´ß»¯¼Á   ¢Ü½«Éú³ÉµÄ°±Òº»¯²¢¼°Ê±´ÓÌåϵÖзÖÀë³öÀ´£¬Î´·´Ó¦µÄN2¡¢H2Ñ­»·µ½ºÏ³ÉËþÖУ®
£¨2£©Ò»¶¨Ìõ¼þÏÂNH3µÄƽºâÌå»ý·ÖÊýËæn£¨N2£©±ä»¯ÈçͼËùʾ
£¨T-ζȣ©£®ÔòT2£¼T1£¨Ì¡¢=¡¢£¼£©£¬ÅжϵÄÒÀ¾ÝÊÇ£ººÏ³É°±·´Ó¦ÊÇ·ÅÈÈ·´Ó¦£¬Î¶ÈÉý¸ß£¬Æ½ºâÏòÄæ·´Ó¦·½ÏòÒÆ¶¯£¬NH3µÄÌå»ý·ÖÊýϽµ£¬ËùÒÔT1£¾T2
£¨3£©Ð´³ö¸Ã·´Ó¦N2£¨g£©+3H2£¨g£©?2NH3£¨g£© µÄƽºâ³£Êý±í´ïʽK=$\frac{{c}^{2}£¨N{H}_{3}£©}{c£¨{N}_{2}£©{c}^{3}£¨{H}_{2}£©}$£®

·ÖÎö £¨1£©ÀÕÉ³ÌØÁÐÔ­ÀíÊÇÈç¹û¸Ä±äÓ°ÏìÆ½ºâµÄÒ»¸öÌõ¼þ£¨ÈçŨ¶È¡¢Ñ¹Ç¿»òζȵȣ©£¬Æ½ºâ¾ÍÏòÄܹ»¼õÈõÕâÖָıäµÄ·½ÏòÒÆ¶¯£¬ÀÕÉ³ÌØÁÐÔ­ÀíÊÊÓõĶÔÏóÓ¦´æÔÚ¿ÉÄæ¹ý³Ì£¬ÈçÓë¿ÉÄæ¹ý³ÌÎ޹أ¬ÓëÆ½ºâÒÆ¶¯Î޹أ¬Ôò²»ÄÜÓÃÀÕÉ³ÌØÁÐÔ­Àí½âÊÍ£»
£¨2£©¶ÔÓÚ·ÅÈÈ·´Ó¦£¬Éý¸ßζȣ¬»¯Ñ§Æ½ºâÏò×ÅÎüÈÈ·½Ïò¼´Äæ·´Ó¦·½Ïò½øÐУ»
£¨3£©ÒÀ¾Ýƽºâ³£Êý¸ÅÄîд³ö£¬ÓÃÉú³ÉÎïŨ¶ÈµÄÃݴη½³Ë»ý³ýÒÔ·´Ó¦ÎïŨ¶ÈµÄÃݴη½³Ë»ý£®

½â´ð ½â£º£¨1£©¢Ù¸ßÓÚ³£Ñ¹£¬Ôö´óѹǿ£¬»¯Ñ§Æ½ºâ»áÕýÏòÒÆ¶¯£¬ÓÐÀûÓÚ°±ÆøµÄºÏ³É£¬ÄÜÓÃÀÕÉ³ÌØÁÐÔ­Àí½âÊÍ£¬¹Ê´íÎó£»
¢Ú500¡æµÄ¸ßΣ¬²»ÓÐÀûÓÚ°±ÆøµÄºÏ³É£¬µ«ÊÇ¿ÉÒÔÌá¸ß´ß»¯¼ÁµÄ´ß»¯»îÐÔ£¬²»ÄÜÓÃÀÕÉ³ÌØÁÐÔ­Àí½âÊÍ£¬¹ÊÕýÈ·£»
¢ÛÌú´¥Ã½×÷´ß»¯¼Á£¬²»»áÒýÆð»¯Ñ§Æ½ºâµÄÒÆ¶¯£¬²»ÄÜÓÃÀÕÉ³ÌØÁÐÔ­Àí½âÊÍ£¬¹ÊÕýÈ·£»
¢Ü½«Éú³ÉµÄ°±Òº»¯²¢¼°Ê±´ÓÌåϵÖзÖÀë³öÀ´£¬Î´·´Ó¦µÄN2¡¢H2Ñ­»·µ½ºÏ³ÉËþÖУ¬¶¼»áʹµÃ»¯Ñ§Æ½ºâÕýÏòÒÆ¶¯£¬ÓÐÀûÓÚ°±µÄºÏ³É£¬ÄÜÓÃÀÕÉ³ÌØÁÐÔ­Àí½âÊÍ£¬¹Ê´íÎó£»
¹ÊÑ¡¢Ú¢Û£»
£¨2£©ºÏ³É°±·´Ó¦ÊÇ·ÅÈÈ·´Ó¦£¬Ëæ×Å·´Ó¦½øÐУ¬ÌåϵζÈÖð½¥Éý¸ß£¬ËùÒÔ»¯Ñ§Æ½ºâ»áÄæÏòÒÆ¶¯£¬µ¼ÖÂNH3µÄÌå»ý·ÖÊýϽµ£¬¼´Î¶ÈÔ½¸ß£¬NH3µÄÌå»ý·ÖÊýԽС£¬ËùÒÔT2£¼T1£¬¹Ê´ð°¸Îª£º£¼£»ºÏ³É°±·´Ó¦ÊÇ·ÅÈÈ·´Ó¦£¬Î¶ÈÉý¸ß£¬Æ½ºâÏòÄæ·´Ó¦·½ÏòÒÆ¶¯£¬NH3µÄÌå»ý·ÖÊýϽµ£¬ËùÒÔT1£¾T2£»
£¨3£©N2£¨g£©+3H2£¨g£©?2NH3£¨g£©£¬·´Ó¦Æ½ºâ³£ÊýµÄ±í´ïʽ K=$\frac{{c}^{2}£¨N{H}_{3}£©}{c£¨{N}_{2}£©{c}^{3}£¨{H}_{2}£©}$£»
¹Ê´ð°¸Îª£º$\frac{{c}^{2}£¨N{H}_{3}£©}{c£¨{N}_{2}£©{c}^{3}£¨{H}_{2}£©}$£®

µãÆÀ ±¾Ì⿼²é½Ï×ۺϣ¬Éæ¼°Ó°ÏìÆ½ºâµÄÒòËØ¡¢»¯Ñ§Æ½ºâͼÏóµÈ£¬×¢Öظ߿¼³£¿¼²éµãµÄ¿¼²é£¬×¢ÒâͼÏóµÄ·ÖÎö£¬ÌâÄ¿ÄѶÈÖеȣ®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø