ÌâÄ¿ÄÚÈÝ

·ÖÀà·¨ÊÇ»¯Ñ§Ñ§Ï°µÄÒ»ÖÖÊ®·ÖÓÐЧµÄ·½·¨£¬Ëü¿ÉÒÔʹÎÒÃÇ´Ó²»Í¬½Ç¶È¶Ôͬһ֪ʶ×ö¸ü¼ÓÉîÈëµÄÁ˽⣬ÈËÃǸù¾Ý²»Í¬µÄ±ê×¼£¬¼´Ê¹Í¬Ò»ÎïÖÊÒ²¿ÉÄܱ»»®ÔÚ²»Í¬µÄÀà±ðÖУ®ÏÖÓÐÈçÏÂÎïÖÊ¢ÙMgCl2 ¢ÚHCl  ¢ÛSO2 ¢ÜNO2  ¢ÝK2CO3  ¢ÞCl2  ¢ßCaO  ¢àNaOHÇë¸ù¾ÝÏÂÁбê×¼£¬¶ÔÉÏÊöÎïÖʽøÐзÖÀࣺ
£¨1£©¼Èº¬Àë×Ó¼üÓÖº¬¹²¼Û¼üµÄÎïÖÊÊÇ
 
£¨Ìî´úºÅ£¬ÏÂͬ£©£®
£¨2£©Ö»º¬¹²¼Û¼üÇÒΪ·Çµç½âÖʵÄÊÇ
 
£®
£¨3£©º¬Óй²¼Û¼üµÄ»¯ºÏÎïÊÇ
 
£®
¿¼µã£º»¯Ñ§¼ü
רÌ⣺»¯Ñ§¼üÓë¾§Ìå½á¹¹
·ÖÎö£º¸ù¾ÝÔªËØ×é³É£¬½áºÏÀë×Ó¼ü¡¢¹²¼Û¼ü¡¢Àë×Ó»¯ºÏÎïÒÔ¼°¹²¼Û»¯ºÏÎï¡¢·Çµç½âÖʵĸÅÄî½øÐÐÅжϣ¬×¢Òâµ¥Öʺͻ¯ºÏÎïµÄÇø±ð£®
½â´ð£º ½â£º¢ÙMgCl2ÊôÓÚÀë×Ó»¯ºÏÎֻº¬ÓÐÀë×Ó¼ü£¬ÊôÓÚµç½âÖÊ£»
¢ÚHClÊôÓÚ¹²¼Û»¯ºÏÎֻº¬¹²¼Û¼ü£¬ÊôÓÚµç½âÖÊ£»
¢ÛSO2ÊôÓÚ¹²¼Û»¯ºÏÎֻº¬¹²¼Û¼ü£¬ÊôÓڷǵç½âÖÊ£»
¢ÜNO2ÊôÓÚ¹²¼Û»¯ºÏÎֻº¬¹²¼Û¼ü£¬ÊôÓڷǵç½âÖÊ£»
¢ÝK2CO3ÊôÓÚÀë×Ó»¯ºÏÎ¼Èº¬ÓÐÀë×Ó¼ü£¬ÓÖº¬Óй²¼Û¼ü£¬ÊôÓÚµç½âÖÊ£»
¢ÞCl2ÊôÓڷǽðÊôµ¥ÖÊ£¬Ö»º¬Óй²¼Û¼ü£¬¼È²»Êǵç½âÖÊÒ²²»ÊǷǵç½âÖÊ£»
¢ßCaOÊôÓÚÀë×Ó»¯ºÏÎֻº¬ÓÐÀë×Ó¼ü£¬ÊôÓÚµç½âÖÊ£»
¢àNaOHÊôÓÚÀë×Ó»¯ºÏÎ¼Èº¬ÓÐÀë×Ó¼ü£¬ÓÖº¬Óй²¼Û¼ü£¬ÊôÓÚµç½âÖÊ£»
¹Ê´ð°¸Îª£º¢Ý¢à£»¢Û¢Ü£»¢Ú¢Û¢Ü¢Ý¢à£®
µãÆÀ£º±¾Ì⿼²é»¯Ñ§¼üµÄ·ÖÀàÒÔ¼°Àë×Ó»¯ºÏÎïÓë¹²¼Û»¯ºÏÎïµÄÅжϣ¬ÌâÄ¿ÄѶȲ»´ó£¬×¢ÒâÏà¹ØÖªÊ¶µÄ°ÑÎÕ£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ʵÑéÊÒÐèÒª0.2mol/L CuSO4ÈÜÒº250mL£¬ÊµÑéÊÒ¿ÉÌṩÅäÖÆÈÜÒºµÄÊÔ¼ÁÓУº¢ÙÀ¶É«µ¨·¯¾§Ì壨CuSO4?5H2O£©  ¢Ú4mol/L CuSO4ÈÜÒº
£¨1£©ÎÞÂÛ²ÉÓúÎÖÖÊÔ¼Á½øÐÐÅäÖÆ£¬ÊµÑ鱨ÐëÓõ½µÄ²£Á§ÒÇÆ÷³ýÉÕ±­¡¢²£Á§°ô¡¢½ºÍ·µÎ¹ÜÍ⣬ÖÁÉÙ»¹ÐèÒªµÄÒ»ÖÖÒÇÆ÷ÊÇ
 
£¬ÔÚʹÓøÃÒÇÆ÷ǰ±ØÐë½øÐеIJÙ×÷ÊÇ
 
£®
£¨2£©ÈôÓõ¨·¯¾§Ìå½øÐÐÅäÖÆ£¬ÐèÓÃÍÐÅÌÌìÆ½³ÆÈ¡CuSO4?5H2OµÄÖÊÁ¿Îª
 
g£»Èç¹ûÓÃ4mol/LµÄCuSO4ÈÜҺϡÊÍÅäÖÆ£¬ÐèÓÃÁ¿Í²Á¿È¡
 
ml 4mol/L CuSO4ÈÜÒº£®
£¨3£©ÊµÑéÊÒÓÃ4mol/LµÄÁòËáÍ­ÈÜҺϡÊÍÅäÖÆÈÜÒºËùÐèµÄʵÑé²½ÖèÓУº
ÆäÖÐÕýÈ·µÄ²Ù×÷˳ÐòΪ
 

¢ÙÍùÉÕ±­ÖмÓÈëÔ¼100mlË®½øÐгõ²½Ï¡ÊÍ£¬ÀäÈ´ÖÁÊÒÎÂ
¢ÚÓÃÁ¿Í²Á¿È¡Ò»¶¨Ìå»ý4mol/L µÄÁòËáÍ­ÈÜÒºÓÚÒ»ÉÕ±­ÖÐ
¢Û¼ÆËãËùÐè4mol/L ÁòËáÍ­ÈÜÒºµÄÌå»ý
¢Ü½«ÈÜÒºµßµ¹Ò¡ÔȺóת´æÓÚÊÔ¼ÁÆ¿
¢Ý¼ÓË®ÖÁÒºÃæÀëÈÝÁ¿Æ¿1-2cm´¦¸ÄÓýºÍ·µÎ¹Ü½øÐж¨ÈÝ
¢ÞÏ´µÓÉÕ±­ºÍ²£Á§°ô2-3´Î²¢½«Ï´µÓҺעÈëÈÝÁ¿Æ¿£¬ÇáÇáÒ¡¶¯ÈÝÁ¿Æ¿£¬Ê¹ÈÜÒº»ìºÏ¾ùÔÈ
¢ß½«ÈÜÒº×ªÒÆÈëÈÝÁ¿Æ¿
£¨4£©ÅäÖÆÈÜÒº¹ý³ÌÖУ¬Èç¹û³öÏÖÒÔÏÂÇé¿ö£¬¶Ô½á¹ûÓкÎÓ°Ï죨Ìî¡°Æ«¸ß¡±¡¢¡°Æ«µÍ¡±»ò¡°ÎÞÓ°Ï족£©
A£®¶¨ÈݺóÈûÉÏÆ¿Èû·´¸´Ò¡ÔÈ£¬¾²Öúó£¬ÒºÃæ²»µ½¿Ì¶ÈÏߣ¬ÔÙ¼ÓË®ÖÁ¿Ì¶ÈÏß
 

B£®¶¨ÈÝʱ¸©Êӿ̶ÈÏß
 

C£®ÈÝÁ¿Æ¿Î´¸ÉÔï¼´ÓÃÀ´ÅäÖÆÈÜÒº
 

£¨5£©ÊµÑé¹ý³ÌÖÐÓõ½ÕôÁóË®£®ÈçͼΪʵÑéÊÒÖÆÈ¡ÕôÁóË®µÄ×°ÖÃʾÒâͼ£®Í¼ÖеÄÁ½´¦Ã÷ÏԵĴíÎóÊÇ
 
£»
 
£®ÊµÑéʱAÖгý¼ÓÈëÉÙÁ¿×ÔÀ´Ë®Í⣬»¹Ðè¼ÓÈëÉÙÁ¿
 
£¬Æä×÷ÓÃÊÇ·ÀÖ¹±©·Ð£®
²»Ðâ¸ÖÒÔÆäÓÅÒìµÄ¿¹¸¯Ê´ÐÔÄÜÔ½À´Ô½Êܵ½ÈËÃǵÄÇàíù£¬ËüÖ÷ÒªÊÇÓÉÌú¡¢¸õ¡¢Äø¡¢Í­¡¢Ì¼µÈÔªËØËù×é³ÉµÄºÏ½ð£®
¢ñ£®ÂÈ»¯ÌúÈÜÒºÓÃÓÚ¼ìÑéʳÓÃÏ㾫ÒÒõ£ÒÒËáÒÒõ¥Ê±£¬»áÉú³É×ÏÉ«ÅäºÏÎÆäÅäÀë×ӽṹÈçͼ1Ëùʾ£®
£¨1£©´ËÅäºÏÎïÖУ¬ÌúÀë×ӵļ۵ç×ÓÅŲ¼Ê½Îª
 
£®
£¨2£©´ËÅäºÏÎïµÄ-C2H5ÖÐC-H¼äÐγɻ¯Ñ§¼üµÄÔ­×Ó¹ìµÀ·Ö±ðÊÇ
 
£»
 
£®
¢ò¡¢£¨1£©ÒÑÖªCrO5ÖÐCrΪ+6¼Û£¬ÔòCrO5µÄ½á¹¹Ê½Îª
 
£®
£¨2£©½ðÊôÄø·ÛÔÚCOÆøÁ÷ÖÐÇá΢¼ÓÈÈ£¬Éú³ÉÎÞÉ«»Ó·¢ÐÔÒºÌåNi£¨CO£©n£¬ÓëNi£¨CO£©nÖÐÅäÌ廥ΪµÈµç×ÓÌåµÄÀë×ӵĻ¯Ñ§Ê½Îª
 
£¨Ð´³öÒ»¸ö¼´¿É£©£®
£¨3£©Í­ÊǵÚËÄÖÜÆÚ×îÖØÒªµÄ¹ý¶ÉÔªËØÖ®Ò»£¬Æäµ¥Öʼ°»¯ºÏÎï¾ßÓй㷺ÓÃ;£®ÒÑÖªCuH¾§Ìå½á¹¹µ¥ÔªÈçͼ2Ëùʾ£®¸Ã»¯ºÏÎïµÄÃܶÈΪ¦Ñg/cm3£¬°¢·ü¼ÓµÂÂÞ³£ÊýµÄֵΪNA£¬Ôò¸Ã¾§°ûÖÐCuÔ­×ÓÓëHÔ­×ÓÖ®¼äµÄ×î¶Ì¾àÀëΪ
 
cm£¨Óú¬¦ÑºÍNAµÄʽ×Ó±íʾ£©£®

¢ó¡¢ÅðÔªËØÔÚ»¯Ñ§ÖÐÓкÜÖØÒªµÄµØÎ»£¬Åð¼°Æä»¯ºÏÎï¹ã·ºÓ¦ÓÃÓÚÓÀ´Å²ÄÁÏ¡¢³¬µ¼²ÄÁÏ¡¢¸»È¼ÁϲÄÁÏ¡¢¸´ºÏ²ÄÁϵȸßвÄÁÏÁìÓòÓ¦Óã®
£¨1£©Èý·ú»¯ÅðÔÚ³£Î³£Ñ¹ÏÂΪ¾ßÓд̱Ƕñ³ôºÍÇ¿´Ì¼¤ÐÔµÄÎÞÉ«Óж¾¸¯Ê´ÐÔÆøÌ壬Æä·Ö×ÓµÄÁ¢Ìå¹¹ÐÍΪ£¬BÔ­×ÓµÄÔÓ»¯ÀàÐÍΪ
 
£®
£¨2£©Á×»¯ÅðÊÇÒ»ÖÖÊܵ½¸ß¶È¹Ø×¢µÄÄÍĥͿÁÏ£¬Ëü¿ÉÓÃ×÷½ðÊôµÄ±íÃæ±£»¤²ã£®Èçͼ3ʾÒâµÄÊÇÁ×»¯ÅðµÄ¾§Ìå½á¹¹µ¥Ôª£¬ÔòÁ×»¯ÅðµÄ»¯Ñ§Ê½Îª£¬Î¢Á£¼ä´æÔÚµÄ×÷ÓÃÁ¦Îª
 
£®
£¨3£©ÕýÅðËᣨH3BO3£©ÊÇÒ»ÖÖÆ¬²ã×´½á¹¹°×É«¾§Ì壬²ãÄÚµÄH3BO3·Ö×Ó¼äͨ¹ýÇâ¼üÏàÁ¬£¨Èçͼ4£©£®
¢Ù1mol H3BO3µÄ¾§ÌåÖÐÓÐ
 
molÇâ¼ü£®
¢ÚÅðËáÈÜÓÚˮӦÉú³ÉÈõµç½âÖÊһˮºÏÅðËáH2O?B£¨OH£©3£¬ËüµçÀëÉú³ÉÉÙÁ¿[B£¨OH£©4]-ºÍµÄH+Àë×Ó£®ÔòÅðËáΪԪËᣬ[B£¨OH£©4]-º¬ÓеĻ¯Ñ§¼üÀàÐÍΪ
 
£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø