题目内容
先化简,再求值:
÷(a+1)×
,其中a=1.
| a2-1 |
| a2+6a+9 |
| a2-9 |
| a-1 |
| a2-1 |
| a2+6a+9 |
| a2-9 |
| a-1 |
=
| (a+1)(a-1) |
| (a+3)2 |
| 1 |
| a+1 |
| (a+3)(a-3) |
| a-1 |
=
| a-3 |
| a+3 |
将a=1代入上式得:
原式=
| a-3 |
| a+3 |
| 1-3 |
| 1+3 |
| 1 |
| 2 |
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题目内容
| a2-1 |
| a2+6a+9 |
| a2-9 |
| a-1 |
| a2-1 |
| a2+6a+9 |
| a2-9 |
| a-1 |
| (a+1)(a-1) |
| (a+3)2 |
| 1 |
| a+1 |
| (a+3)(a-3) |
| a-1 |
| a-3 |
| a+3 |
| a-3 |
| a+3 |
| 1-3 |
| 1+3 |
| 1 |
| 2 |