题目内容
计算:
(1)3(x2)3-2(x3)2
(2)3a(2a2-9a+3)-4a(2a-1)
(3)先化简,再求值:(x-1)(x-2)-3x(x+3)+2(x+2)(x-1),其中x=
.
(1)3(x2)3-2(x3)2
(2)3a(2a2-9a+3)-4a(2a-1)
(3)先化简,再求值:(x-1)(x-2)-3x(x+3)+2(x+2)(x-1),其中x=
| 1 |
| 3 |
考点:整式的混合运算—化简求值,整式的混合运算
专题:
分析:(1)先算乘方,再合并即可;
(2)先算乘法,再合并同类项即可;
(3)先算乘法,再合并同类项,最后代入求出即可.
(2)先算乘法,再合并同类项即可;
(3)先算乘法,再合并同类项,最后代入求出即可.
解答:解:(1)原式=3x6-2x6
=x6;
(2)原式=6a3-27a2+9a-8a2+4a
=6a3-35a2+13a;
(3)(x-1)(x-2)-3x(x+3)+2(x+2)(x-1)
=x2-3x+2-3x2-9x+2x2+2x-4
=-10x-2,
当x=
时,原式=-10×
-2=-
.
=x6;
(2)原式=6a3-27a2+9a-8a2+4a
=6a3-35a2+13a;
(3)(x-1)(x-2)-3x(x+3)+2(x+2)(x-1)
=x2-3x+2-3x2-9x+2x2+2x-4
=-10x-2,
当x=
| 1 |
| 3 |
| 1 |
| 3 |
| 16 |
| 3 |
点评:本题考查了整式的混合运算和求值的应用,主要考查学生的计算能力,难度适中.
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