题目内容
(1)| 3-x |
| 2x-4 |
| 5 |
| x-2 |
| x |
| x-1 |
| 1 |
| x2-x |
分析:(1)首先利用分式的加减运算法则计算括号里面的,然后再利用分式的乘除运算法则求得结果;
(2)先通分,然后进行四则运算,最后将x=2代入.
(2)先通分,然后进行四则运算,最后将x=2代入.
解答:解:(1)
÷(x+2-
)
=
÷
=
•
=-
.
(2)(1-
)÷
=
•x(x-1)
=-x.
把x=2代入,上式=-2.
| 3-x |
| 2x-4 |
| 5 |
| x-2 |
=
| 3-x |
| 2(x-2) |
| (x+3)(x-3) |
| x-2 |
=
| 3-x |
| 2(x-2) |
| x-2 |
| (x+3)(x-3) |
=-
| 1 |
| 2(x+3) |
(2)(1-
| x |
| x-1 |
| 1 |
| x2-x |
=
| x-1-x |
| x-1 |
=-x.
把x=2代入,上式=-2.
点评:此题考查了分式的混合运算和分式的化简求值,分式的混合运算中通分、因式分解和约分是解答的关键.解题时还要注意运算顺序.分式的化简求值解答的关键是把分式化到最简,然后代值计算.
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