题目内容

4.化简下列各题:
(1)4x2-8x+5-3x2+6x-4
(2)3x2+2xy-4y2-(3xy-4y2+3x2
(3)(5x2-3y2)-[(5x2-2xy-y2)-2(3y2-xy)].

分析 (1)找出同类项,再合并同类项即可;
(2)先去括号,再找出同类项,合并同类项即可;
(3)先去小括号,再去中括号,最后合并同类项即可.

解答 解:(1)4x2-8x+5-3x2+6x-4
=(4-3)x2+(-8+6)x+(5-4)
=x2-2x+1;

(2)3x2+2xy-4y2-(3xy-4y2+3x2
=3x2+2xy-4y2-3xy+4y2-3x2
=-xy;

(3)(5x2-3y2)-[(5x2-2xy-y2)-2(3y2-xy)]
=5x2-3y2-[5x2-2xy-y2-6y2+2xy]
=5x2-3y2-5x2+2xy+y2+6y2-2xy]
=4y2

点评 本题考查了整式的加减的应用,能正确合并同类项是解此题的关键.

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