题目内容
先化简,再求值:3x2y-[5xy2+2(x2y-
)+x2y ]+6xy2,其中x=-2,y=
.
| 1 |
| 2 |
| 1 |
| 2 |
原式=3x2y-[5xy2+2x2y-1+x2y]+6xy2
=3x2y-5xy2-3x2y+1+6xy2
=xy2+1,
当x=-2,y=
时,原式=-2×(
)2+1=
.
=3x2y-5xy2-3x2y+1+6xy2
=xy2+1,
当x=-2,y=
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
练习册系列答案
相关题目