题目内容
9.解关于x,y的方程组$\left\{\begin{array}{l}{x+y=4k}\\{x-y=5k}\end{array}\right.$,并求当解满足方程4x-3y=21时的k值.分析 先利用原方程组求出x、y,当然x、y都是用k表示的代数式.最后根据4x-3y=21解出k的数值.
解答 解:方程组$\left\{\begin{array}{l}{x+y=4k}\\{x-y=5k}\end{array}\right.$的解为$\left\{\begin{array}{l}{x=4.5k}\\{y=-0.5k}\end{array}\right.$,
把$\left\{\begin{array}{l}{x=4.5k}\\{y=-0.5k}\end{array}\right.$代入4x-3y=21得:18k+1.5k=21,
解得:k=$\frac{14}{13}$.
点评 本题考查了考查二元一次方程组的解,解决本题的关键是求出x,y的值.
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