题目内容
计算与化简:
(1)
-
×
(2)
÷
×
(3)(
+
)÷
(4)1-
÷
.
(1)
| 24 |
| 18 |
|
(2)
| ||
|
|
|
(3)(
| 3 |
| x-2 |
| 2 |
| x+2 |
| 5x2+2x |
| x2-4 |
(4)1-
| a-1 |
| a |
| a2-1 |
| a2+2a |
分析:(1)先算乘法,再算减法;
(2)先把各二次根式化为最简二次根式,再进行计算;
(3)先通分计算括号里面的加法,再将除法转化为乘法,约分化简即可求解;
(4)先将除法转化为乘法,再因式分解,约分化简即可.
(2)先把各二次根式化为最简二次根式,再进行计算;
(3)先通分计算括号里面的加法,再将除法转化为乘法,约分化简即可求解;
(4)先将除法转化为乘法,再因式分解,约分化简即可.
解答:解:(1)
-
×
=2
-
=
;
(2)
÷
×
=
×
×
=
;
(3)(
+
)÷
=
•
=
;
(4)1-
÷
=1-
•
=1-
=-
.
| 24 |
| 18 |
|
=2
| 6 |
| 6 |
=
| 6 |
(2)
| ||
|
|
|
=
| 3 | ||
2
|
| ||
| 3 |
| ||
| 2 |
=
| ||
| 6 |
(3)(
| 3 |
| x-2 |
| 2 |
| x+2 |
| 5x2+2x |
| x2-4 |
=
| 3(x+2)+2(x-2) |
| (x+2)(x-2) |
| (x+2)(x-2) |
| x(5x+2) |
=
| 1 |
| x |
(4)1-
| a-1 |
| a |
| a2-1 |
| a2+2a |
=1-
| a-1 |
| a |
| a(a+2) |
| (a+1)(a-1) |
=1-
| a+2 |
| a+1 |
=-
| 1 |
| a+1 |
点评:本题考查的是二次根式的混合运算,在进行此类运算时,一般先把二次根式化为最简二次根式的形式后再运算.同时考查了分式的混合运算.
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