题目内容
已知
+
=4,则
=
.
| 1 |
| x |
| 1 |
| y |
| 3x+xy+3y |
| x-xy+y |
| 13 |
| 3 |
| 13 |
| 3 |
分析:由
+
=4,得出x+y=4xy,把代数式中的x+y代换为4xy,进一步计算得出结果.
| 1 |
| x |
| 1 |
| y |
解答:解:∵
+
=4,
∴x+y=4xy,
则
=
=
=
=
.
故答案为:
.
| 1 |
| x |
| 1 |
| y |
∴x+y=4xy,
则
| 3x+xy+3y |
| x-xy+y |
=
| 3(x+y)+xy |
| (x+y)-xy |
=
| 3×4xy+xy |
| 4xy-xy |
=
| 13xy |
| 3xy |
=
| 13 |
| 3 |
故答案为:
| 13 |
| 3 |
点评:此题考查代数式求值,注意利用已知条件和代数式的特点,合理转换,整体代入;解决此题也可把xy代换为x+y.
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