题目内容
化简:(| x-1 |
| x+1 |
| x+1 |
| x+2 |
| x+3 |
| x2+4x+4 |
分析:本题要注意运算顺序,有括号先算括号里的,再把除法转化为乘法来做,经过分解因式、约分把结果化为最简.
解答:解:(
-
)÷
=
•
=
•
=-
.
| x-1 |
| x+1 |
| x+1 |
| x+2 |
| x+3 |
| x2+4x+4 |
=
| (x-1)(x+2)-(x+1)2 |
| (x+1)(x+2) |
| (x+2)2 |
| x+3 |
=
| x2+x-2-x2-2x-1 |
| x+1 |
| x+2 |
| x+3 |
=-
| x+2 |
| x+1 |
点评:此题的关键是通分、分解因式、约分.用到了几个公式:(x+a)(x+b)=x2+(a+b)x+ab,a2±2ab+b2=(a±b)2.
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