题目内容
(1)计算:(-2)0+(| 1 |
| 3 |
| 12 |
(2)请你先化简(
| x+1 |
| x |
| x |
| x-1 |
| 1 |
| (x-1)2 |
分析:(1)利用指数的性质.
(2)先对
-
通分,再化简求值,代值必须使原分式有意义.
(2)先对
| x+1 |
| x |
| x |
| x-1 |
解答:解:(1)原式=1+3-
=4-
=4-2
;
(2)原式=
×(x-1)2=-
,
当x=2时,原式=-
;
当x=-2时,原式=-
.
| 12 |
| 12 |
| 3 |
(2)原式=
| x2-1-x2 |
| x(x-1) |
| x-1 |
| x |
当x=2时,原式=-
| 1 |
| 2 |
当x=-2时,原式=-
| 3 |
| 2 |
点评:考查指数的性质和分式化简求值.注意x=0,1时,分式无意义.
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