题目内容
化简：（
+
）÷
| 4 |
| x2-4 |
| 1 |
| x+2 |
| 1 |
| x-2 |
原式=[
+
]÷
=
•(x-2)
=1．
| 4 |
| (x+2)(x-2) |
| x-2 |
| (x+2)(x-2) |
| 1 |
| x-2 |
=
| x+2 |
| (x+2)(x-2) |
=1．
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题目内容
| 4 |
| x2-4 |
| 1 |
| x+2 |
| 1 |
| x-2 |
| 4 |
| (x+2)(x-2) |
| x-2 |
| (x+2)(x-2) |
| 1 |
| x-2 |
| x+2 |
| (x+2)(x-2) |