题目内容
先化简,再求值:
÷(1+
),其中x=2cos30°.
| x |
| x2-1 |
| 1 |
| x-1 |
原式=
÷
=
×
=
,
∵x=2×
=
,
∴原式=
=
.
| x |
| (x+1)(x-1) |
| x |
| x-1 |
=
| x |
| (x+1)(x-1) |
| x-1 |
| x |
=
| 1 |
| x+1 |
∵x=2×
| ||
| 2 |
| 3 |
∴原式=
| 1 | ||
|
| ||
| 2 |
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