题目内容
先化简,再求值:| x |
| x+2 |
| 10 |
| x2-4 |
| 5 |
| x-2 |
| x3-x2 |
| x2+x-2 |
| 1 | ||
|
分析:先把分式化简,再把x的值化简,最后代入求值.
解答:解:原式=
-
×
+
=
+
=
=x-1.
∵x=-4+
+1+2=
-1,
∴原式=x-1=
-2.
| x |
| x+2 |
| 10 |
| (x+2)(x-2) |
| x-2 |
| 5 |
| x2(x-1) |
| (x+2)(x-1) |
=
| x-2 |
| x+2 |
| x2 |
| x+2 |
| (x+2)(x-1) |
| x+2 |
∵x=-4+
| 2 |
| 2 |
∴原式=x-1=
| 2 |
点评:考查了分式的混合运算以及实数的基本运算.
练习册系列答案
相关题目