题目内容
计算:
(1)
•(
-2)-4
(2)
(
-
-6
)-2(
-
).
(1)
| ||||
|
| 5 |
(2)
| 1 |
| 3 |
| 108 |
4
|
|
|
| 1 |
| 3 |
| 27 |
考点:二次根式的混合运算
专题:
分析:(1)首先利用分数的性质化简,进而利用平方差进行计算得出即可;
(2)首先化简二次根式,进而合并求出即可.
(2)首先化简二次根式,进而合并求出即可.
解答:解:(1)
•(
-2)-4
=(
+2)•(
-2)-4
=5-4-4
=-3;
(2)
(
-
-6
)-2(
-
)
=
(6
-
-6×
)-2(
-
)
=2
-
-2
-
+2
=2
-2
.
| ||||
|
| 5 |
=(
| 5 |
| 5 |
=5-4-4
=-3;
(2)
| 1 |
| 3 |
| 108 |
4
|
|
|
| 1 |
| 3 |
| 27 |
=
| 1 |
| 3 |
| 3 |
3
| ||
| 2 |
| ||
| 3 |
| ||
| 4 |
| 3 |
=2
| 3 |
3
| ||
| 2 |
| 3 |
| ||
| 2 |
| 3 |
=2
| 3 |
| 2 |
点评:此题主要考查了二次根式的混合运算,正确化简二次根式是解题关键.
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