题目内容
先化简,再求值:| x |
| x-1 |
| 3 |
| (x-1)(x+2) |
| 2 |
| 3 |
分析:本题可先找到最简公分母(x-1)(x+2),通分、约分得到最简形式,再把数代入求值.
解答:解:
-
-1=
=
=
=
;
∴当x=-
时,原式的值为
=
.
| x |
| x-1 |
| 3 |
| (x-1)(x+2) |
| x(x+2)-3-(x-1)(x+2) |
| (x-1)(x+2) |
=
| x2+2x-3-x2-2x+x+2 |
| (x-1)(x+2) |
=
| x-1 |
| (x-1)(x+2) |
=
| 1 |
| x+2 |
∴当x=-
| 2 |
| 3 |
| 1 | ||
-
|
| 3 |
| 4 |
点评:本题考查了分式的化简与求值,主要的知识点是通分、约分等.
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