题目内容
| x2+1 |
| x2-1 |
| x |
| x+1 |
分析:首先将分式通分,然后利用同分母的分式相加减的运算法则求解即可,注意结果需化为最简.
解答:解:
-
=
-
=
=
=
.
| x2+1 |
| x2-1 |
| x |
| x+1 |
| x2+1 |
| (x+1)(x-1) |
| x(x-1) |
| (x+1)(x-1) |
| x2+1-x2+x |
| (x+1)(x-1) |
| x+1 |
| (x+1)(x-1) |
| 1 |
| x-1 |
点评:此题考查了分式的加减运算.此题难度不大,解题的关键是注意准确通分,注意结果需化为最简.
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