题目内容
3.计算题(1)4-5×(-$\frac{1}{2}$)3
(2)(-2)+3-(-4)+(+2)
(3)-$\frac{3}{2}$÷(-7)×(+2$\frac{4}{5}$)
(4)-(-3)2×2-[-(1-0.2÷$\frac{3}{5}$)×(-3)2]
(5)(-$\frac{1}{6}$-$\frac{1}{36}$+$\frac{3}{4}$-$\frac{1}{12}$)×(-48)
(6)(-4)×(-2$\frac{1}{7}$)+(-8)×(-2$\frac{1}{7}$)+12×(-2$\frac{1}{7}$)
分析 (1)先计算乘方运算,再加减;
(2)去括号,写成省略加号的形式,进行计算;
(3)先确定符号,再从左往右依次计算;
(4)先计算括号里的,再计算乘方,注意负号;
(5)利用乘法分配律展开,再相乘;
(6)利用乘法分配律的逆运算,提取-2$\frac{1}{7}$,比较简便.
解答 解:(1)4-5×(-$\frac{1}{2}$)3,
=4-5×(-$\frac{1}{8}$),
=4+$\frac{5}{8}$,
=4$\frac{5}{8}$;
(2)(-2)+3-(-4)+(+2),
=-2+3+4+2,
=7;
(3)-$\frac{3}{2}$÷(-7)×(+2$\frac{4}{5}$),
=$\frac{3}{2}$×$\frac{1}{7}$×$\frac{14}{5}$,
=$\frac{3}{5}$;
(4)-(-3)2×2-[-(1-0.2÷$\frac{3}{5}$)×(-3)2],
=-9×2-[-(1-$\frac{2}{10}$×$\frac{5}{3}$)×9],
=-18-[-(1-$\frac{1}{3}$)×9],
=-18-[-$\frac{2}{3}$×9],
=-18+6,
=-12;
(5)(-$\frac{1}{6}$-$\frac{1}{36}$+$\frac{3}{4}$-$\frac{1}{12}$)×(-48),
=-$\frac{1}{6}$×(-48)-$\frac{1}{36}$×(-48)+$\frac{3}{4}$×(-48)-$\frac{1}{12}$×(-48),
=8+$\frac{4}{3}$-36+4,
=12-36+$\frac{4}{3}$,
=-24+1+$\frac{1}{3}$,
=-23+$\frac{1}{3}$,
=-22$\frac{2}{3}$;
(6)(-4)×(-2$\frac{1}{7}$)+(-8)×(-2$\frac{1}{7}$)+12×(-2$\frac{1}{7}$),
=-2$\frac{1}{7}$×(-4-8+12),
=-$\frac{15}{7}$×0,
=0.
点评 此题主要考查了有理数的混合运算,要熟练掌握,注意明确有理数混合运算顺序:先算乘方,再算乘除,最后算加减;同级运算,应按从左到右的顺序进行计算;如果有括号,要先做括号内的运算.