题目内容
13.若方程组$\left\{\begin{array}{l}{4x+3y=1}\\{kx+(k-1)y=3}\end{array}\right.$的解中x与y的值相等,则k的值是11.分析 根据方程组$\left\{\begin{array}{l}{4x+3y=1}\\{kx+(k-1)y=3}\end{array}\right.$的解中x与y的值相等,可以求得k的值,从而可以解答本题.
解答 解:∵方程组$\left\{\begin{array}{l}{4x+3y=1}\\{kx+(k-1)y=3}\end{array}\right.$的解中x与y的值相等,
∴$\left\{\begin{array}{l}{4x+3x=1}\\{kx+(k-1)x=3}\end{array}\right.$,
解得,$\left\{\begin{array}{l}{x=\frac{1}{7}}\\{k=11}\end{array}\right.$,
即k的值是11,
故答案为:11.
点评 本题考查二元一次方程组的解,解答本题的关键是明确二元一次方程组的解得意义.
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