题目内容

7.方程组$\left\{\begin{array}{l}2x+y=a\\ x+y=3\end{array}\right.$的解为$\left\{\begin{array}{l}x=2\\ y=b\end{array}\right.$,则a、b的值分别为(  )
A.1,2B.5,1C.2,1D.2,3

分析 把$\left\{\begin{array}{l}x=2\\ y=b\end{array}\right.$代入方程组$\left\{\begin{array}{l}2x+y=a\\ x+y=3\end{array}\right.$,即可解答.

解答 解:把$\left\{\begin{array}{l}x=2\\ y=b\end{array}\right.$代入方程组$\left\{\begin{array}{l}2x+y=a\\ x+y=3\end{array}\right.$得:$\left\{\begin{array}{l}{4+b=a}\\{2+b=3}\end{array}\right.$
解得:$\left\{\begin{array}{l}{a=5}\\{b=1}\end{array}\right.$
故选:B.

点评 本题主要考查了二元一次方程组的解,解题的关键是用代入法进行求解.

练习册系列答案
相关题目

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网