题目内容
如图,在平面直角坐标系内,试写出△ABC各顶点的坐标,并求△ABC的面积.

由图可知:A点的坐标是(6,6),B(0,3),C(3,0).
所以,S△ABC=S正方形AEOD-S△AEB-S△OBC-S△ACD
=6×6-
×3×6-
×3×3-
×3×6
=36-9-
-9
=17
.

所以,S△ABC=S正方形AEOD-S△AEB-S△OBC-S△ACD
=6×6-
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
=36-9-
| 9 |
| 2 |
=17
| 1 |
| 2 |
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