题目内容
如图,已知⊙O中,弦AC、BD相交于点P,AB=5,AP=3,DP=2,则CD=______.
∵∠ABD=∠ACD(同弧所对的圆周角相等),∠APB=∠CPD(对顶角相等),
∴△ABP∽△DCP,
∴
| AB |
| DC |
| AP |
| DP |
又AB=5,AP=3,DP=2,
∴
| 5 |
| DC |
| 3 |
| 2 |
解得DC=
| 10 |
| 3 |
| 10 |
| 3 |
故答案是:
| 10 |
| 3 |
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题目内容
| AB |
| DC |
| AP |
| DP |
| 5 |
| DC |
| 3 |
| 2 |
| 10 |
| 3 |
| 10 |
| 3 |
| 10 |
| 3 |