题目内容
已知a+
=3,求
(1)a2+
的值;
(2)a3-a2-5a+2010的值.
| 1 |
| a |
(1)a2+
| 1 |
| a2 |
(2)a3-a2-5a+2010的值.
(1)∵a+
=3,
∴a2+
=(a+
)2-2=32-2=7
(2)a3-a2-5a+2010
=a3+a-a2-6a+2010
=a2(a+
)-a2-6a+2010
=3a2-a2-6a+2010
=2a2-6a+2010
=2a2+2-6a+2008
=2a(a+
)-6a+2008
=6a-6a+2008
=2008
| 1 |
| a |
∴a2+
| 1 |
| a2 |
| 1 |
| a |
(2)a3-a2-5a+2010
=a3+a-a2-6a+2010
=a2(a+
| 1 |
| a |
=3a2-a2-6a+2010
=2a2-6a+2010
=2a2+2-6a+2008
=2a(a+
| 1 |
| a |
=6a-6a+2008
=2008
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