题目内容
(| x2-4 |
| x2-4x+4 |
| x-2 |
| x+2 |
| x |
| x-2 |
分析:首先把括号里的式子进行通分,然后把除法运算转化成乘法运算,进行约分化简.
解答:解:原式=[
-
}×
=
×
=
.
故答案为
.
| (x+2)(x-2) |
| (x-2)2 |
| x-2 |
| x+2 |
| x-2 |
| x |
=
| 8x |
| (x-2)(x+2) |
| x+2 |
| x |
=
| 8 |
| x-2 |
故答案为
| 8 |
| x-2 |
点评:本题主要考查分式的混合运算,通分、因式分解和约分是解答的关键.
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)÷
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| x2-4 |
| x2-4x+4 |
| 2-x |
| x+2 |
| x |
| x-2 |
A、-
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B、
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C、-
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D、
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