题目内容
化简:(| 1 |
| x-y |
| 1 |
| x+y |
| 2y |
| x2+2xy+y2 |
分析:首先利用分式的加减运算法则计算括号里面的,然后再利用分式的乘除运算法则求得结果即可解答.
解答:解:(
-
)÷
=
÷
=
=
.
| 1 |
| x-y |
| 1 |
| x+y |
| 2y |
| x2+2xy+y2 |
=
| 2y |
| x2-y2 |
| 2y |
| x2+2xy+y2 |
=
| (x+y)2 |
| x2-y2 |
=
| x+y |
| x-y |
点评:此题考查了分式的混合运算,通分、因式分解和约分是解答的关键.解题时还要注意运算顺序.
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