题目内容
计算:
(1)
-
(2)
÷
•(a+3)
(3)
+
-
(4)(2-
)2-(2+
)(2-
)+
.
(1)
| a2 |
| a+3 |
| 9 |
| a+3 |
(2)
| 2a-4 |
| a2+6a+9 |
| a-2 |
| a+3 |
(3)
| 27 |
|
| 2 | ||
|
(4)(2-
| 3 |
| 3 |
| 3 |
| 1 | ||
|
(1)原式=
=
=a-3;
(2)原式=
•
•(a+3)
=2;
(3)原式=3
+
-
=
-
;
(4)原式=4-2
+3-(4-3)+2-
=4-2
+3-1+2-
=8-3
.
| a2-9 |
| a+3 |
=
| (a+3)(a-3) |
| a+3 |
=a-3;
(2)原式=
| 2(a-2) |
| (a+3)2 |
| a+3 |
| a-2 |
=2;
(3)原式=3
| 3 |
| ||
| 3 |
| 2 |
=
10
| ||
| 3 |
| 2 |
(4)原式=4-2
| 3 |
| 3 |
=4-2
| 3 |
| 3 |
=8-3
| 3 |
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