题目内容
计算题:
(1)(4
-4
+3
)÷2
;(2)(-2)2-(
)-1×
+(1-
)0.
(1)(4
6 |
|
8 |
2 |
2 |
8 |
3 |
(1)原式=(4
-2
+6
)×
=4
-2+6
=4
+4;
(2)原式=4-
×2
+1
=4-2+1
=3.
6 |
2 |
2 |
| ||
2 |
=4
3 |
=4
3 |
(2)原式=4-
| ||
2 |
2 |
=4-2+1
=3.
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