题目内容
计算:
(1)(1+
)÷
(2)
-a-1.
(1)(1+
| 1 |
| x |
| x2-1 |
| x |
(2)
| a2 |
| a-1 |
(1)原式=
•
=
;
(2)原式=
=
.
| x+1 |
| x |
| x |
| (x+1)(x-1) |
| 1 |
| x-1 |
(2)原式=
| a2-(a+1)(a-1) |
| a-1 |
| 1 |
| a-1 |
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题目内容
| 1 |
| x |
| x2-1 |
| x |
| a2 |
| a-1 |
| x+1 |
| x |
| x |
| (x+1)(x-1) |
| 1 |
| x-1 |
| a2-(a+1)(a-1) |
| a-1 |
| 1 |
| a-1 |