题目内容
已知x2-4x+1=0,求代数式(
+
)÷
的值.
| x+3 |
| x-2 |
| 1 |
| 2-x |
| x2-4 |
| 3 |
原式=(
-
)×
=
×
=
=
.
∵x2-4x+1=0,
∴x2-4x=-1,
∴原式=
=1.
| x+3 |
| x-2 |
| 1 |
| x-2 |
| 3 |
| (x+2)(x-2) |
=
| x+2 |
| x-2 |
| 3 |
| (x+2)(x-2) |
=
| 3 |
| (x-2)2 |
=
| 3 |
| x2-4x+4 |
∵x2-4x+1=0,
∴x2-4x=-1,
∴原式=
| 3 |
| -1+4 |
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