Question

11．写出二元一次方程x+3y=13的一个正整数解为$\left\{\begin{array}{l}{x=1}\\{y=4}\end{array}\right.$或$\left\{\begin{array}{l}{x=4}\\{y=3}\end{array}\right.$或$\left\{\begin{array}{l}{x=7}\\{y=2}\end{array}\right.$或$\left\{\begin{array}{l}{x=10}\\{y=1}\end{array}\right.$（任意一个即可）．

Answer 1

分析 直接利用二元一次方程分别得出符合题意的解．

解答 解：当x=1，y=4；
当x=4时，y=3；
当x=7时，y=2；
当x=10时，y=1．
故答案为：$\left\{\begin{array}{l}{x=1}\\{y=4}\end{array}\right.$或$\left\{\begin{array}{l}{x=4}\\{y=3}\end{array}\right.$或$\left\{\begin{array}{l}{x=7}\\{y=2}\end{array}\right.$或$\left\{\begin{array}{l}{x=10}\\{y=1}\end{array}\right.$（任意一个即可）．

点评 此题主要考查了解二元一次方程，正确掌握解题方法是解题关键．