题目内容
计算:
(1)
-
;
(2)(
-
)÷
.
(1)
| 2a |
| a2-9 |
| 1 |
| a-3 |
(2)(
| 1 |
| a |
| 1 |
| b |
| a2-b2 |
| ab |
(1)原式=
-
=
=
;
(2)原式=
•
=-
•
=-
.
| 2a |
| (a+3)(a-3) |
| a+3 |
| (a+3)(a-3) |
=
| a-3 |
| (a+3)(a-3) |
=
| 1 |
| a+3 |
(2)原式=
| b-a |
| ab |
| ab |
| (a+b)(a-b) |
=-
| a-b |
| ab |
| ab |
| (a+b)(a-b) |
=-
| 1 |
| a+b |
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