题目内容
已知x2-5x-2014=0,求代数式
÷
的值.
| (x-2)3-(x-1)2+1 |
| x2-4x+4 |
| 2x |
| 2x2-4x |
∵x2-5x-2014=0,
∴x2-5x=2014,
∴原式=
×
=
=(x-2)2-
+
=(x-2)2-
=(x-2)2-
=(x-2)2-x
=x2-5x+4
=2014+4
=2018;
∴x2-5x=2014,
∴原式=
| (x-2)3-(x-1)2+1 |
| (x-2)2 |
| 2x(x-2) |
| 2x |
| (x-2)3-(x-1)2+1 |
| x-2 |
=(x-2)2-
| (x-1)2 |
| x-2 |
| 1 |
| x-2 |
=(x-2)2-
| (x-1)2-1 |
| x-2 |
=(x-2)2-
| x(x-2) |
| x-2 |
=(x-2)2-x
=x2-5x+4
=2014+4
=2018;
练习册系列答案
相关题目