题目内容
计算:
-
÷
.
| x+1 |
| x-1 |
| x2-2x |
| x2-1 |
| x2-x-2 |
| x2+2x+1 |
考点:分式的混合运算
专题:
分析:先把要求的式子进行因式分解,再把除法转化成乘法,然后约分,最后合并即可得出答案.
解答:解:
-
÷
=
-
÷
=
-
×
=
-
=
.
| x+1 |
| x-1 |
| x2-2x |
| x2-1 |
| x2-x-2 |
| x2+2x+1 |
| x+1 |
| x-1 |
| x(x-2) |
| (x+1)(x-1) |
| (x-2)(x+1) |
| (x+1)2 |
| x+1 |
| x-1 |
| x(x-2) |
| (x+1)(x-1) |
| (x+1)2 |
| (x-2)(x+1) |
| x+1 |
| x-1 |
| x |
| x-1 |
| 1 |
| x-1 |
点评:此题考查了分式的混合运算,通分、因式分解和约分是解答本题的关键,注意在解题时要把分式化到最简.
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