题目内容
先化简,再求值:
-
•
,其中x=1.
| x |
| x+1 |
| x+3 |
| x+1 |
| x2-2x+1 |
| x2+4x+3 |
| x |
| x+1 |
| x+3 |
| x+1 |
| x2-2x+1 |
| x2+4x+3 |
=
| x |
| x+1 |
| x+3 |
| x+1 |
| (x-1)2 |
| (x+1)(x+3) |
=
| x |
| x+1 |
| (x-1)2 |
| (x+1)2 |
=
| x(x+1)-(x-1)2 |
| (x+1)2 |
=
| 3x-1 |
| (x+1)2 |
当x=1时,原式=
| 3-1 |
| (1+1)2 |
| 1 |
| 2 |
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