ÌâÄ¿ÄÚÈÝ
8£®»¯Ñ§ÓëÉú»îϢϢÏà¹Ø£¬ÎÒÃǵÄÉú»îÀë²»¿ª»¯Ñ§£®£¨1£©¹ú¼ÒÌᳫʹÓüӵâÑΣ¬ÊÇÔÚʳÑÎÖмÓÈëÊýÁ¿µÄµâËá¼Ø£¬¼ÓµâʳÑÎÀïµÄ¡°µâ¡±ÊÇÖ¸ÔªËØ£¨Ìî¡°µ¥ÖÊ¡±¡°ÔªËØ¡±»ò¡°Ô×Ó¡±£©£®
£¨2£©Ä³Æ·ÅÆµÄ¿ÕÆø¾»»¯¼Áº¬ÓйýÑõ»¯ÄÆ£¨Na2O2£©£¬Ëü¿ÉÒÔʹÊÒÄڵĶþÑõ»¯Ì¼×ª»¯ÎªÌ¼ËáÄÆºÍÑõÆø£¬Ð´³öÆä»¯Ñ§·´Ó¦·½³Ìʽ2Na2O2+2CO2=2Na2CO3+O2£®
£¨3£©²»Ð¡Ðı»Îó涣ҧ£¨Îóæ·ÖÃÚ³öÒÏËᣩ£¬ÏÂÁÐÎïÖÊ¿ÉÓÃÓÚͿĨÒÔ¼õÇáÌÛÍ´µÄÊÇC£®
A£®Ê³´× B£®Ê³ÑÎË® C£®·ÊÔíË® D£®ÇâÑõ»¯ÄÆÈÜÒº
£¨4£©ÍºÍÌúÒ»ÑùÒ²ÈÝÒ×ÉúÐ⣬ÍÐâµÄÖ÷Òª³É·ÖÊǼîʽ̼ËáÍ£¨Cu2£¨OH£©2CO3£©£¬ÊÇÍÓë¿ÕÆøÖеÄÑõÆø¡¢Ë®ºÍ¶þÑõ»¯Ì¼¹²Í¬×÷ÓõĽá¹û£®
·ÖÎö £¨1£©Ê³Æ·¡¢Ò©Æ·¡¢ÓªÑøÆ·¡¢¿óȪˮµÈÎïÖÊÖеġ°µâ¡±µÈ²»ÊÇÒÔµ¥ÖÊ¡¢·Ö×Ó¡¢Ô×ÓµÈÐÎʽ´æÔÚ£¬¶øÊÇÖ¸ÔªËØ£¬Í¨³£ÓÃÔªËØ¼°ÆäËùÕ¼ÖÊÁ¿£¨ÖÊÁ¿·ÖÊý£©À´ÃèÊö£®
£¨2£©¹ýÑõ»¯ÄÆÓë³µÏáÀïµÄ¶þÑõ»¯Ì¼×ª»¯ÎªÌ¼ËáÄÆºÍÑõÆø£¬Ð´³ö·´Ó¦µÄ»¯Ñ§·½³Ìʽ¼´¿É£»
£¨3£©¸ù¾ÝÖкͷ´Ó¦µÄÔÀí£¬²»Ð¡Ðı»Îó涣ҧ£¬ÎóæÄÜ·ÖÃÚ³öÒÏËáʹÈËÆ¤·ôÖ×Í´£¬ÎªÁ˼õÇáÈ˵ÄÑ÷Í´£¬¿ÉÒÔͿĨÏÔ¼îÐÔµÄÎïÖʽøÐзÖÎö£®
£¨4£©¸ù¾ÝÖÊÁ¿Êغ㶨ÂÉ¡¢¿ÕÆøµÄ³É·Ö¼°ÍÐâµÄÖ÷Òª³É·Ö¼îʽ̼Ëá͵Ä×é³ÉÔªËØ·ÖÎö£®
½â´ð ½â£º£¨1£©¡°¼ÓµâʳÑΡ±Öеġ°µâ¡±²»ÊÇÒÔµ¥ÖÊ¡¢·Ö×Ó¡¢Ô×ÓµÈÐÎʽ´æÔÚ£¬ÕâÀïËùÖ¸µÄ¡°µâ¡±ÊÇÇ¿µ÷´æÔÚµÄÔªËØ£¬Óë¾ßÌåÐÎ̬Î޹أ®¹ÊÌî£ºÔªËØ£»
£¨2£©¹ýÑõ»¯ÄÆÓë³µÏáÀïµÄ¶þÑõ»¯Ì¼×ª»¯ÎªÌ¼ËáÄÆºÍÑõÆø£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ2Na2O2+2CO2=2Na2CO3+O2£®¹Ê´ð°¸Îª£º2Na2O2+2CO2=2Na2CO3+O2£®
£¨3£©²»Ð¡Ðı»Îó涣ҧ£¬ÎóæÄÜ·ÖÃÚ³öÒÏËáʹÈËÆ¤·ôÖ×Í´£¬ÎªÁ˼õÇáÈ˵ÄÑ÷Í´£¬¿ÉÒÔͿĨÏÔ¼îÐÔµÄÎïÖÊ£®
A¡¢Ê³´×ÏÔËáÐÔ£¬²»ÄÜÓÃÓÚͿĨ£¬¹ÊA´íÎó£»
B¡¢Ê³ÑÎË®ÏÔÖÐÐÔ£¬²»ÄÜÓÃÓÚͿĨ£¬¹ÊB´íÎó£»
C¡¢·ÊÔíË®ÏÔ¼îÐÔ£¬¿ÉÓÃÓÚͿĨÒÔ¼õÇáÌÛÍ´£¬¹ÊCÕýÈ·£»
D¡¢ÇâÑõ»¯ÄÆÈÜÒºÏÔ¼îÐÔ£¬µ«¾ßÓи¯Ê´ÐÔ£¬²»ÄÜÓÃÓÚͿĨ£¬¹ÊD´íÎó£®
¹ÊÑ¡£ºC£®
£¨4£©ÓÉÓÚÍÐâµÄÖ÷Òª³É·ÖÊǼîʽ̼ËáÍ£¨Cu2£¨OH£©2CO3£©£®º¬ÓÐÍ¡¢Ì¼¡¢Ñõ¡¢ÇâÔªËØ£¬ËùÒÔ£¬ÍÉúÐâ³ýÁËÓë¿ÕÆøÖеÄÑõÆø¡¢Ë®ÓйØÍ⣬»¹ÐèÒªÓë¿ÕÆøÖк¬ÓÐÌ¼ÔªËØµÄÎïÖÊÓйأ¬´ËÎïÖÊÊǶþÑõ»¯Ì¼£»¹ÊÌ¶þÑõ»¯Ì¼£®
µãÆÀ ±¾Ì⿼²éÁ˵Ä֪ʶµã½Ï¶à£¬µ«ÊÇÊôÓÚ»ù±¾»¯Ñ§ÖªÊ¶µÄ¿¼²é£¬ÄѶȲ»´ó£®
£¨1£©ÒÇÆ÷aµÄÃû³ÆÊdz¤¾±Â©¶·£»
£¨2£©ÒÔAΪ·¢Éú×°Öã¬ÓøßÃÌËá¼ØÖÆÈ¡ÑõÆø£¬»¯Ñ§·½³ÌʽΪ2KMnO4$\frac{\underline{\;\;¡÷\;\;}}{\;}$K2MnO4+MnO2+O2¡ü£¬ÊԹܿڷÅÒ»ÍÅÃÞ»¨µÄ×÷ÓÃÊÇ·ÀÖ¹¼ÓÈÈʱ¸ßÃÌËá¼Ø·ÛÄ©½øÈëµ¼¹Ü£»
£¨3£©ÒÔBΪ·¢Éú×°ÖÃÖÆÈ¡¶þÑõ»¯Ì¼£¬¼ÓÈëҩƷ֮ǰҪÏȼì²é×°ÖÃµÄÆøÃÜÐÔ£¬ÊÕ¼¯¶þÑõ»¯Ì¼Í¨³£Ñ¡ÓÃC£¨Ìî±êºÅ£©£»
£¨4£©Î¶ȡ¢Å¨¶È¡¢¹ÌÌåµÄ¿ÅÁ£´óСµÈÒòËØ»áÓ°Ïì·´Ó¦ËÙÂÊ£®ÎªÑо¿ÊµÑéÊÒÖÆÈ¡¶þÑõ»¯Ì¼µÄÊÊÒËÌõ¼þ£¬½øÐÐÈç±íËÄ×éʵÑ飺
| ¼× | ÒÒ | ±û | ¶¡ | |
| mg´óÀíʯ | ¿é×´ | ¿é×´ | ·Ûĩ״ | ·Ûĩ״ |
| mgÑéË㣨¹ýÁ¿£© | Ï¡ÑÎËá | ŨÑÎËá | Ï¡ÑÎËá | ŨÑÎËá |
¢ÚʵÑé¼×Óë±û¶ÔÕÕ£¨Ìî±àºÅ£©£¬ÊÇΪÁËÑо¿¹ÌÌå·´Ó¦Îï¿ÅÁ£´óС¶Ô·´Ó¦ËÙÂʵÄÓ°Ï죻
¢ÛÉÏÊöʵÑéÖУ¬ÁíÒ»¸öÓ°Ïì·´Ó¦ËÙÂʵÄÒòËØÊÇÑÎËáµÄŨ¶È£®
| A£® | ÓÃСËÕ´ò±ºÖƸâµã | B£® | Ó͹øÖеÄÓÍ×Å»ðÓùø¸Ç¸ÇÃð | ||
| C£® | ¶¬ÌìÓÃúȡůʱ·â±ÕÃÅ´° | D£® | ÓùýµÄ²Ëµ¶ÓÃĨ²¼²Á¸É·ÅÖ÷ÀÉúÐâ |
¢ÙFeS2+11O2$\frac{\underline{\;¸ßÎÂ\;}}{\;}$2Fe2O3+8SO2 ¢ÚFe2O3+3CO$\frac{\underline{\;¸ßÎÂ\;}}{\;}$2Fe+3CO2
¢Û2SO2+O2$\frac{\underline{\;\;\;¸ßÎÂ\;\;\;}}{´ß»¯¼Á}$2SO3 ¢ÜSO3+H2O=H2SO4
ÔªËØµÄ»¯ºÏ¼Û·¢Éú±ä»¯µÄÊÇ£¨¡¡¡¡£©
| A£® | ¢Ù¢Ú¢Û | B£® | ¢Ù¢Ú¢Ü | C£® | ¢Ú¢Û¢Ü | D£® | ¢Ù¢Û¢Ü |
| A£® | ´¿¼î¡¡¡¡ Na2CO3¡¡ ¼î¡¡ ÖÆ²£Á§ | B£® | Éúʯ»Ò¡¡ CaO¡¡ Ñõ»¯Îï¡¡ ²¹¸Æ¼Á | ||
| C£® | ʳÑΡ¡ NaCl¡¡ ÑΡ¡ ³ýÌúÐâ | D£® | »ð¼î¡¡¡¡¡¡NaOH¡¡¡¡¼î¡¡¡¡¡¡¡¡¡¡È¥ÓÍÎÛ |