ÌâÄ¿ÄÚÈÝ
7£®ÈçͼËùʾ£¬Ë®Æ½ÃæÉÏÏà¾à¦É=0.5mµÄÁ½¸ù¹â»¬Æ½ÐнðÊôµ¼¹ìMNºÍPQ£¬ËûÃǵĵç×è¿ÉºöÂÔ²»¼Æ£¬ÔÚMºÍPÖ®¼ä½ÓÓÐ×î´ó×èֵΪ6.0¦¸µÄ»¬¶¯±ä×èÆ÷R£¬µ¼Ìå°ôabµç×èr=1¦¸£¬Óëµ¼¹ì´¹Ö±ÇÒ½Ó´¥Á¼ºÃ£¬Õû¸ö×°Öô¦ÓÚ·½ÏòÊúÖ±ÏòϵÄÔÈÇ¿´Å³¡ÖУ¬´Å¸ÐӦǿ¶ÈB=0.4T£¬»¬¶¯±ä×èÆ÷»¬Æ¬´¦ÔÚÕýÖмäλÖã¬abÔÚÍâÁ¦F×÷ÓÃÏÂÒÔ¦Ô=l0m/sµÄËÙ¶ÈÏòÓÒÔÈËÙÔ˶¯£¬ÒÔÏÂÅжÏÕýÈ·µÄÊÇ£¨¡¡¡¡£©A£® | ͨ¹ýµ¼Ìå°ôµÄµçÁ÷´óСΪ0.5A£¬·½ÏòÓÉbµ½a | |
B£® | µ¼Ìå°ôÊܵ½µÄ°²ÅàÁ¦´óСΪ1N£¬·½ÏòˮƽÏò×ó | |
C£® | ÍâÁ¦FµÄ¹¦ÂÊ´óСΪ1W | |
D£® | ÈôÔö´ó»¬¶¯±ä×èÆ÷ÏûºÄµÄ¹¦ÂÊ£¬Ó¦°Ñ»¬Æ¬ÏòM¶ËÒƶ¯ |
·ÖÎö ¸ù¾ÝÇиʽÇó½â¸ÐÓ¦µç¶¯ÊÆ£¬¸ù¾ÝÅ·Ä·¶¨ÂÉÇó½â¸ÐÓ¦µçÁ÷£¬¸ù¾ÝÓÒÊÖ¶¨ÔòÅжϸÐÓ¦µçÁ÷·½Ïò£¬¸ù¾Ý×óÊÖ¶¨ÔòÅжϰ²ÅàÁ¦·½Ïò£»¶ÔÓÚµçÔ´£¬µ±µç·µÄÄÚ¡¢Íâµç×èÏàµÈʱ£¬µçÔ´µÄÊä³ö¹¦ÂÊ×î´ó£®
½â´ð ½â£ºAB¡¢Çиîµç¶¯ÊÆΪ£ºE=BLv=0.4¡Á0.5¡Á10=2V£¬
¸ÐÓ¦µçÁ÷´óСΪ£ºI=$\frac{E}{r+R}=\frac{2}{1+3}A=0.5A$£¬
¸ù¾ÝÓÒÊÖ¶¨Ôò£¬¸ÐÓ¦µçÁ÷·½ÏòΪ£ºa¡úb£»
°²ÅàÁ¦´óСΪ£ºFA=BIL=0.4¡Á0.5¡Á0.5=0.1N£¬
¸ù¾Ý×óÊÖ¶¨Ôò£¬°²ÅàÁ¦Ë®Æ½Ïò×ó£»¹ÊA´íÎó£¬B´íÎó£»
C¡¢µ¼Ìå°ôÔÈËÙÔ˶¯£¬¸ù¾ÝÆÑ»ãÌÁ·£¬ÀÁ¦ÎªF=FA=0.1N£¬
¹ÊÀÁ¦µÄ¹¦ÂÊΪ£ºP=Fv=0.1¡Á10=1W£¬¹ÊCÕýÈ·£»
D¡¢µ¼Ìå°ôÏ൱ÓÚµçÔ´£¬µ±Íâµç×èÓëÄÚµç×èÔ½Êǽӽü£¬Íâµç×èÏûºÄµÄ¹¦ÂÊÔ½´ó£¬¹ÊÒªÔö´ó»¬¶¯±ä×èÆ÷ÏûºÄµÄ¹¦ÂÊ£¬Ó¦°Ñ»¬Æ¬ÏòM¶ËÒƶ¯£¬¹ÊDÕýÈ·£»
¹ÊÑ¡£ºCD
µãÆÀ ±¾Ì⿼²é»¬¸ËÎÊÌ⣬¹Ø¼üÊÇÊìÁ·ÔËÓÃÇиʽ¡¢°²ÅàÁ¦¹«Ê½¡¢×óÊÖ¶¨Ôò¡¢ÓÒÊÖ¶¨Ôò£¬Í¬Ê±Ã÷È·µç·µÄÄÚÍâµç×èÏàµÈʱµçÔ´µÄÊä³ö¹¦ÂÊ×î´ó£®
A£® | Á½´Å³¡µÄ´Å¸ÐӦǿ¶È B1£ºB2Ϊ111£º141 | |
B£® | Á½´Å³¡µÄ´Å¸ÐӦǿ¶È B1£ºB2Ϊ111£º2 | |
C£® | º¤Ô×Ӻ˺ÍRgÔ×Ӻ˸÷×ÔÐýתµÚÒ»°ëÔ²µÄʱ¼ä±ÈΪ111£º141 | |
D£® | º¤Ô×Ӻ˺ÍRgÔ×Ӻ˸÷×ÔÐýתµÚÒ»°ëÔ²µÄʱ¼ä±ÈΪ2£º141 |
A£® | СÇòÔÚ°Ú¶¯¹ý³ÌÖÐÊܵ½µÄÍâÁ¦µÄºÏÁ¦¼´ÎªÏòÐÄÁ¦ | |
B£® | ÔÚ×î¸ßµãA¡¢B£¬ÒòСÇòµÄËÙ¶ÈΪ0£¬ËùÒÔСÇòÊܵ½µÄºÏÍâÁ¦Îª0 | |
C£® | СÇòÔÚ×îµÍµãCËùÊܵĺÏÍâÁ¦£¬¼´ÎªÏòÐÄÁ¦ | |
D£® | СÇòÔÚ°Ú¶¯¹ý³ÌÖÐʹÆäËÙÂÊ·¢Éú±ä»¯µÄÁ¦ÎªÉþ×ÓµÄÀÁ¦ |