题目内容
给定四条曲线:①x2+y2=
;②
+
=1;?③x2+
=1;④
+y2=1.其中与直线x+y-5=0仅有一个交点的曲线是( )
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823132419222227.gif)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823132419238254.gif)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823132419254353.gif)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823132419254353.gif)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823132419285246.gif)
A.①②③ | B.②③④ | C.①②④ | D.①③④ |
D
将y=
-x分别代入四条曲线的方程:
代入①,得4x2-4
x+5=0,Δ=0;
代入②,得13x2-18
x+9=0,Δ>0;
代入③,得5x2-2
x+1=0,Δ=0;
代入④,得5x2-8
x+16=0,Δ=0.
∴①③④仅与x+y-
=0有一个交点.
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823132419300170.gif)
代入①,得4x2-4
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823132419300170.gif)
代入②,得13x2-18
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823132419300170.gif)
代入③,得5x2-2
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823132419300170.gif)
代入④,得5x2-8
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823132419300170.gif)
∴①③④仅与x+y-
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823132419300170.gif)
![](http://thumb.zyjl.cn/images/loading.gif)
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