题目内容
(12分) 设数列
的前n项和为
,
为等比数列,且
.
(1)求数列
和
的通项公式;
(2)设
,求数列
的前n项和
.

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

(1)求数列


(2)设



(1)
(2)


(2)



本试题主要是考查了数列的通项公式和数列求和的综合运用。
(1)对于n=1,和n》2分为两种情况进行研究通项公式和前n项和的关系式得到结论。
(2)由(1)得,
,
,所以
,再结合通项公式的特点,裂项求和得到结论。
解:(1) 当

故
的等差数列. 3分
设{bn}的公比为
故
6分
(2) 由(1)得,
,
∴
∴

12分
(1)对于n=1,和n》2分为两种情况进行研究通项公式和前n项和的关系式得到结论。
(2)由(1)得,



解:(1) 当


故

设{bn}的公比为

故

(2) 由(1)得,


∴

∴


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